Ta có: $\widehat{A} = 180^{\circ} - \widehat{B} - \widehat{C} = 180^{\circ} - 79^{\circ} - 61^{\circ} = 40^{\circ}$
Áp dụng định lí sin, ta có: $\frac{a}{sinA}$ = $\frac{b}{sinB}$ = $\frac{c}{sinC}$ = 2R
Suy ra:
b = $\frac{a. sinB}{sinA}$ = $\frac{152. sin79^{\circ}}{sin40^{\circ}}$ $\approx$ 232.1
c = $\frac{a.sinC}{sinA}$ = $\frac{152. sin61^{\circ}}{sin40^{\circ}}$ $\approx$ 206,8
R = $\frac{a}{2sinA}$ = $\frac{152}{2sin40}$ $\approx$ 118,2