Giải câu 17 bài Ôn tập cuối năm.
\((u+v-w)'\) | \(=u'+v'-w'\) |
\((ku)'\) | \(=ku'\)(k là hằng số) |
\((uv)'\) | \(=u'v+uv'\) |
\(\left ( \frac{u}{v} \right )'\) | \(=\frac{u'v-uv'}{v^2}(v=v(x)\neq 0)\) |
\(\frac{1}{v}\) | \(=-\frac{v'}{v^2}(v=v(x)\neq 0)\) |
\(y'_x\) | \(=y'_u.u'_x\) |
\((x^n)’=nx^{n-1}\) | \((u^n)’=nu^{n-1}.u’\) |
\(\left ( \frac{1}{x} \right )’=-\frac{1}{x^2}\) | \(\left ( \frac{1}{u} \right )’=-\frac{u’}{u^2}\) |
\((\sqrt{x})’=\frac{1}{2\sqrt{x}}\) | \((\sqrt{u})’=\frac{u’}{2\sqrt{u}}\) |
\((sin\,x)’=cos\,x\) | \((sin\,u)’=u’.cos\,u\) |
\((cos\,x)’=-sin\,x\) | \((cos\,u)’=-u’.sin\,u\) |
\(\left ( tan\,x \right )'=\frac{1}{cos^2x}\) | \(\left ( tan\,u \right )'=\frac{u’}{cos^2u}\) |
\(\left ( cot\,x \right )'=-\frac{1}{sin^2x}\) | \(\left ( cot\,u \right )'=-\frac{u’}{sin^2u}\)
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