Cho dãy số $(u_{n})$, biết $u_{n}=(\frac{n-1}{n+1})^{2n+3}$. Tìm số hạng $u_{n+1}$

Question

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4 câu trả lời

Answer 1

$u_{n+1}=(\frac{n-1}{n+1})^{2(n+1)+3}$

Answer 2

$u_{n+1}=(\frac{n-1}{n+1})^{2(n+1)+3}$

Answer 3

$u_{n+1}=(\frac{n}{n+2})^{2n+3}$

Answer 4

$u_{n+1}=(\frac{n}{n+2})^{2n+5}$