Ta có: 0.1(235) = 1.(235)/10 = (1 + 0.(235)) / 10.
Đặt x = 0(235) thì 1000x = 235.(235) = 235 + x, suy ra 999x = 235 nên $x= \frac{235}{999}$.
Do đó $0.1(235)=(1+\frac{235}{999})/10=\frac{1234}{9990}$
Ta có: 0.1(235) = 1.(235)/10 = (1 + 0.(235)) / 10.
Đặt x = 0(235) thì 1000x = 235.(235) = 235 + x, suy ra 999x = 235 nên $x= \frac{235}{999}$.
Do đó $0.1(235)=(1+\frac{235}{999})/10=\frac{1234}{9990}$