Ta có: $6= \sqrt{36}>\sqrt{35}$ suy ra $6-\sqrt{35}>0$
do đó $\left | 6-\sqrt{35} \right |+5+\sqrt{35}=(6-\sqrt{35})+5+\sqrt{35}=11$
Ta có: $6= \sqrt{36}>\sqrt{35}$ suy ra $6-\sqrt{35}>0$
do đó $\left | 6-\sqrt{35} \right |+5+\sqrt{35}=(6-\sqrt{35})+5+\sqrt{35}=11$