a) $-0.375+\frac{1}{4}-(-\frac{1}{5})=\frac{3}{40}$
b) $\frac{2}{3}+(\frac{-5}{12})+(\frac{-7}{15})+(-0.2)=-\frac{5}{12}$
c) $0.275+(\frac{-8}{17})+\frac{29}{40}+(\frac{-9}{17})-1\frac{1}{3}=\frac{11}{40}+\frac{29}{40}+(\frac{-8}{17})+(\frac{-9}{17})-1\frac{1}{3}=-1\frac{1}{3}$
d) $(-5)\times (\frac{-34}{21})\times (\frac{-7}{10})\times (-\frac{3}{17})=(-0.5)\times (\frac{-34}{21})\times (-\frac{3}{17})\times (\frac{-7}{10})=(-5)\times \frac{2}{7}\times (\frac{-7}{10})=1$
e) $(\frac{13}{18}/\frac{26}{9})\times \frac{4}{7}=(\frac{13}{18}\times \frac{9}{26})\times \frac{4}{7}=\frac{1}{7}$
f) $[(-\frac{5}{33})/\frac{2}{11}]\times 0.15=[(-\frac{5}{33})\times \frac{11}{2}]\frac{3}{20}=\frac{-1}{8}$