Giải bài 7.25 trang 38 toán 7 tập 2 kết nối tri thức.
a) (x2–x).(2x2–x–10)
=x2.2x2+x2.(−x)+x2.(−10)+(−x).2x2+(−x).(−x)+(−x).(−10)
=2x4–x3–10x2–2x3+x2+10x
=2x4–3x3–9x2+10x
b) (0,2x2–3x).5(x2–7x+3)
=(0,2x2–3x).(5x2–35x+15)
=0,2x2.5x2+0,2x2.(−35x)+0,2x2.15+(−3x).5x2+(−3x).(−35x)+(−3x).15
=x4–7x3+3x2–15x3+105x2–45x
=x4–22x3+108x2–45x