$\widehat{C}= 180^{o} – $\widehat{A} – $\widehat{B} = 65^{o}$
$2R=\frac{a}{sinA}\Rightarrow R=5\sqrt{2}$
áp dụng định lí sin, ta có: $\frac{a}{sin A}=\frac{b}{sin B}=\frac{c}{sin C}=2R$
$ \Rightarrow b \approx 13,3 ; c\approx 12,8$
$\widehat{C}= 180^{o} – $\widehat{A} – $\widehat{B} = 65^{o}$
$2R=\frac{a}{sinA}\Rightarrow R=5\sqrt{2}$
áp dụng định lí sin, ta có: $\frac{a}{sin A}=\frac{b}{sin B}=\frac{c}{sin C}=2R$
$ \Rightarrow b \approx 13,3 ; c\approx 12,8$