a) $(8x^{6}-4x^{5}+12x^{4}-20x^{3}) : 4x^{3}$ = $(8x^{6}-4x^{5}+12x^{4}-20x^{3}) : 4x^{3}\\= (8x^{6}:4x^{3})-(4x^{5}:4x^{3})+(12x^{4}: 4x^{3})-(20x^{3}: 4x^{3})\\=2x^{3}-x^{2}+3x-5$
b)
Vậy $(2x^{2}-5x+3) : (2x-3)$ = x - 1
a) $(8x^{6}-4x^{5}+12x^{4}-20x^{3}) : 4x^{3}$ = $(8x^{6}-4x^{5}+12x^{4}-20x^{3}) : 4x^{3}\\= (8x^{6}:4x^{3})-(4x^{5}:4x^{3})+(12x^{4}: 4x^{3})-(20x^{3}: 4x^{3})\\=2x^{3}-x^{2}+3x-5$
b)
Vậy $(2x^{2}-5x+3) : (2x-3)$ = x - 1