a) $3\frac{1}{5}$ = $\frac{3\times 5 + 1}{5}$ = $\frac{16}{5}$
b) $8\frac{4}{7}$ = $\frac{8\times 7 + 4}{7}$ = $\frac{60}{7}$
c) $12\frac{5}{12}$ = $\frac{12\times 12 + 5}{12}$ = $\frac{149}{12}$
a) $3\frac{1}{5}$ = $\frac{3\times 5 + 1}{5}$ = $\frac{16}{5}$
b) $8\frac{4}{7}$ = $\frac{8\times 7 + 4}{7}$ = $\frac{60}{7}$
c) $12\frac{5}{12}$ = $\frac{12\times 12 + 5}{12}$ = $\frac{149}{12}$