a) $3\frac{1}{2}$ + $2\frac{1}{5}$ = $\frac{7}{2}$ + $3\frac{11}{5}$ = $\frac{35}{10}$ + $3\frac{22}{10}$ = $3\frac{57}{10}$
b) $8\frac{1}{3}$ - $5\frac{1}{2}$ = $\frac{25}{3}$ - $\frac{11}{2}$ = $\frac{50}{6}$ - $\frac{33}{6}$ = $\frac{17}{6}$
c) $6\frac{1}{7}$ x $5\frac{6}{43}$ = $\frac{43}{7}$ x $\frac{49}{43}$ = $\frac{2107}{301}$ = $\frac{301}{43}$
d) $9\frac{1}{5}$ : $4\frac{3}{5}$ = $\frac{46}{5}$ : $\frac{23}{5}$ = $\frac{46}{5}$ x $\frac{5}{23}$ = $\frac{230}{115}$ = 2