Ta có: $\widehat{A1}=\widehat{A3}=\widehat{B1}=\widehat{B3}=60^{\circ}$
$\widehat{A2}=\widehat{A4}=\widehat{B2}=\widehat{B4}= 180^{\circ}-60^{\circ}=120^{\circ}$
Đáp án sai: D
Ta có: $\widehat{A1}=\widehat{A3}=\widehat{B1}=\widehat{B3}=60^{\circ}$
$\widehat{A2}=\widehat{A4}=\widehat{B2}=\widehat{B4}= 180^{\circ}-60^{\circ}=120^{\circ}$
Đáp án sai: D