Tính đạo hàm của hàm số $y=\frac{cos2x}{3x+1}$

Question

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4 câu trả lời

Answer 1

$y'=\frac{-2(3x+1)sin2x-3cos2x}{(3x+1)^{2}}$

Answer 2

$y'=\frac{-2(3x+1)sin2x-3cos2x}{3x+1}$

Answer 3

$y'=\frac{-(3x+1)sin2x-3cos2x}{(3x+1)^{2}}$

Answer 4

$y'=\frac{2(3x+1)sin2x-3cos2x}{(3x+1)^{2}}$