Tìm $\int x \sin x (2 x + 1) d x$

Question

Cơ bản

Tìm

\int x \sin x (2 x + 1) d x

4 câu trả lời

Answer 1

\int x \sin x (2 x + 1) d x = - \frac{1}{3} x \cos (2 x + 1) + \frac{1}{4} \sin (2 x + 1) + C

Answer 2

\int x \sin x (2 x + 1) d x = \frac{1}{2} x \cos (2 x + 1) + \frac{1}{4} \sin (2 x + 1) + C

Answer 3

\int x \sin x (2 x + 1) d x = \frac{1}{3} x \cos (2 x + 1) + \frac{1}{4} \sin (2 x + 1) + C

Answer 4

A.

\int x \sin x (2 x + 1) d x = - \frac{1}{2} x \cos (2 x + 1) + \frac{1}{4} \sin (2 x + 1) + C

Tìm ∫xsin⁡x(2x+1)dx