Tìm I= $\int (x - 2 \sin x) \frac{d x}{\cos^{2} x}$

Question

Cơ bản

Tìm I=

\int (x - 2 \sin x) \frac{d x}{\cos^{2} x}

4 câu trả lời

Answer 1

I=

x \tan x - \frac{1}{\cos^{2} x} - \frac{2}{\cos x} + C

Answer 2

I=

x \tan x + l n | \cos x | - \frac{2}{\cos x} + C

Answer 3

I=

x \tan x + l n | \cos x | + \frac{2}{\cos x} + C

Answer 4

I=

x \tan x + \frac{1}{\cos^{2} x} + \frac{2}{\cos x} + C

Tìm I= ∫(x−2sin⁡x)dxcos2⁡x