Tìm I= $\int \frac{dx}{\sin x\sin 2x}$

Question

Cơ bản

4 câu trả lời

Answer 1

I= $-\frac{1}{2\sin x}+ \frac{1}{2}ln|\frac{1- \sin x}{1+ \sin x}+ C$

Answer 2

I= $-\frac{1}{2t}+ \frac{1}{2}ln|\frac{1- t}{1+ t}+ C$

Answer 3

I= $-\frac{1}{2\sin x}+ \frac{1}{4}ln|\frac{1+ \sin x}{1- \sin x}+ C$

Answer 4

I= $-\frac{1}{2t}+ \frac{1}{4}ln|\frac{1+ t}{1- t}+ C$