Tìm I= $\int \frac{d x}{\sin x \sin 2 x}$

Question

Cơ bản

Tìm I=

\int \frac{d x}{\sin x \sin 2 x}

4 câu trả lời

Answer 1

I=

- \frac{1}{2 \sin x} + \frac{1}{2} l n | \frac{1 - \sin x}{1 + \sin x} + C

Answer 2

I=

- \frac{1}{2 t} + \frac{1}{2} l n | \frac{1 - t}{1 + t} + C

Answer 3

I=

- \frac{1}{2 \sin x} + \frac{1}{4} l n | \frac{1 + \sin x}{1 - \sin x} + C

Answer 4

I=

- \frac{1}{2 t} + \frac{1}{4} l n | \frac{1 + t}{1 - t} + C

Tìm I= ∫dxsin⁡xsin⁡2x