Nếu $\tan \frac{\beta }{2}= 3\tan \frac{\alpha }{2}$ thì: $\tan\frac{

Question

Cơ bản

Nếu $\tan \frac{\beta }{2}= 3\tan \frac{\alpha }{2}$ thì: $\tan\frac{(\alpha +\beta )}{2}$ theo $\alpha $ là?

4 câu trả lời

Answer 1

$\frac{2\sin \alpha}{2\cos \alpha-1}$

Answer 2

$\frac{2\cos \alpha}{2\sin \alpha- 1}$

Answer 3

$\frac{2\sin \alpha}{2\sin \alpha- 1}$

Answer 4

$\frac{2\cos \alpha }{2\sin \alpha+ 1}$