Cho tam giác ABC cân tại A, đường cao AH và BK. Ta có:

Question

Cơ bản

5 câu trả lời

Answer 1

$\frac{1}{BK^{2}}=\frac{1}{2BC^{2}}+\frac{1}{2AH^{2}}$

Answer 2

$\frac{1}{BK^{2}}=\frac{1}{3BC^{2}}+\frac{1}{AH^{2}}$

Answer 3

$\frac{1}{BK^{2}}=\frac{1}{BC^{2}}+\frac{1}{4AH^{2}}$

Answer 4

$\frac{1}{BK^{2}}=\frac{1}{BC^{2}}+\frac{1}{2AH^{2}}$

Answer 5

$\frac{1}{BK^{2}}=\frac{1}{BC^{2}}+\frac{1}{AH^{2}}$