Ta có: $\bar{x}=103$
$\Rightarrow s^2=\frac{(112-103)^2+(102-103)^2+(106-103)^2+(94-103)^2+(101-103)^2}{5}=35,2$
$\Rightarrow s \approx 5,94$
Ta có: $\bar{x}=103$
$\Rightarrow s^2=\frac{(112-103)^2+(102-103)^2+(106-103)^2+(94-103)^2+(101-103)^2}{5}=35,2$
$\Rightarrow s \approx 5,94$