$2\frac{3}{5}= \frac{2\times 5+3}{5}=\frac{13}{5}$
$5\frac{4}{9}= \frac{5\times 9+4}{9}=\frac{49}{9}$
$9\frac{3}{8}= \frac{9\times 8+3}{8}=\frac{75}{8}$
$12\frac{7}{10}= \frac{12\times 10+7}{8}=\frac{127}{10}$
$2\frac{3}{5}= \frac{2\times 5+3}{5}=\frac{13}{5}$
$5\frac{4}{9}= \frac{5\times 9+4}{9}=\frac{49}{9}$
$9\frac{3}{8}= \frac{9\times 8+3}{8}=\frac{75}{8}$
$12\frac{7}{10}= \frac{12\times 10+7}{8}=\frac{127}{10}$